(4/7)^5x=(343/64)^-2x=1

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Solution for (4/7)^5x=(343/64)^-2x=1 equation: 



(4/7)^5x=(343/64)^-2x=1

We move all terms to the left:

(4/7)^5x-((343/64)^-2x)=0



Domain of the equation: 7)^5x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 64)^-2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+4/7)^5x-((+343/64)^-2x)=0

We calculate fractions


(-2x)+256^)/7^5x*64)^-2x))+(-2401^5x/7^5x*64)^-2x))=0

We can not solve this equation

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